sql - Query Results For Consecutive Months In Column Grouped By Value -

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the following sample data:

name | hours | rdate       | company | ------------------------------------    |0      |2014-08-01   |w    |0      |2014-07-01   |w    |0      |2014-06-01   |w    |0      |2014-05-01   |w b    |0      |2014-08-01   |x c    |0      |2014-07-01   |y c    |0      |2014-06-01   |y d    |0      |2014-08-01   |v      d    |0      |2014-07-01   |z

the following results desire:

name | hours | rdate       | company | ------------------------------------    |0      |2014-08-01   |w    |0      |2014-07-01   |w    |0      |2014-06-01   |w    |0      |2014-05-01   |w c    |0      |2014-07-01   |y c    |0      |2014-06-01   |y

so question is:

how results of rdate consecutive months in columns i.e 2014-08-01, 2014-07-01(2014-08-01, 2014-06-01 not satisfy)for same name , same company

i'm thinking variation of grouping islands of contiguous dates problem.

;with cte as(     select *,         rn = dateadd(month, - row_number() on (partition name, company order rdate), rdate)     test ) ,ctecount as(     select *,         cc = count(*) over(partition name, company, rn)     cte ) select     name, hours, rdate, company ctecount cc > 1

sql fiddle


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