python - How to determine screen size in matplotlib -
i looking way screen size in pixels using matplotlib interactive backend (e.g. tkagg, qt4agg, or macosx).
i trying write function can open window @ set of standard locations on screen e.g. right half of screen, or top-right corner.
i wrote working solution here, copied below, requires 1 use full_screen_toggle() (as suggested here) create full-screen window measure size.
i looking way screen size without creating full-screen window , changing size.
import matplotlib.pyplot plt def move_figure(position="top-right"): ''' move , resize window set of standard positions on screen. possible positions are: top, bottom, left, right, top-left, top-right, bottom-left, bottom-right ''' mgr = plt.get_current_fig_manager() mgr.full_screen_toggle() # primitive works screen size py = mgr.canvas.height() px = mgr.canvas.width() d = 10 # width of window border in pixels if position == "top": # x-top-left-corner, y-top-left-corner, x-width, y-width (in pixels) mgr.window.setgeometry(d, 4*d, px - 2*d, py/2 - 4*d) elif position == "bottom": mgr.window.setgeometry(d, py/2 + 5*d, px - 2*d, py/2 - 4*d) elif position == "left": mgr.window.setgeometry(d, 4*d, px/2 - 2*d, py - 4*d) elif position == "right": mgr.window.setgeometry(px/2 + d, 4*d, px/2 - 2*d, py - 4*d) elif position == "top-left": mgr.window.setgeometry(d, 4*d, px/2 - 2*d, py/2 - 4*d) elif position == "top-right": mgr.window.setgeometry(px/2 + d, 4*d, px/2 - 2*d, py/2 - 4*d) elif position == "bottom-left": mgr.window.setgeometry(d, py/2 + 5*d, px/2 - 2*d, py/2 - 4*d) elif position == "bottom-right": mgr.window.setgeometry(px/2 + d, py/2 + 5*d, px/2 - 2*d, py/2 - 4*d) if __name__ == '__main__': # usage example move_figure() plt.figure(1) plt.plot([0, 1]) move_figure("top-right") plt.figure(2) plt.plot([0, 3]) move_figure("bottom-right")
this works os x:
import appkit [(screen.frame().size.width, screen.frame().size.height) screen in appkit.nsscreen.screens()]
the apple document on nsscreen
class.
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