python - how to ignore special characters when using word boundry -

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s = '!sopa !sop !sopaa !sopii'

how ignore ! when using word boundary

re.sub(r'\b\!sop\b', 'sopa', s)

output : '!sopa !sop !sopaa !sopii'

seems want this.

>>> s = '!sopa !sop !sopaa !sopii' >>> re.sub(r'\b!sop\b', 'sopa', s) '!sopa sopa !sopaa !sopii'

your regex fail because there isn't \b exits before ! symbol. is, above you're trying match ! symbol if it's preceded non-word character. \b matches between word char , non-word character, vice versa. \b matches between 2 word , 2 non-word chars. here \b actaully exists between space , !, since both non-word characters.


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