regex - excel VB regexp 5.5 capturing group -


i have problem using regexp in excel macro, calling regex.execute(string), instead of getting array of returned capturing groups, single return whole string specified in pattern. using same pattern in http://www.regexr.com/, can see return nicely grouped. missing this:

private sub parsefilename(strinput string)     dim regex new regexp     dim strpattern string     dim strreplace      'sample string \\work_dir\ftp\results\reva\ftp_01_01_06_results\4f\acc2x2r33371_sasssd_run1     strpattern = "ftp_(\w+)_results\\(\w+)\\([\d,\d]+)_(sas|sata)(hdd|ssd)_run(\d)"      regex         .global = true         .multiline = false         .ignorecase = false         .pattern = strpattern     end      if regex.test(strinput)         set strreplace = regex.execute(strinput)         activecell.offset(0, 1) = strreplace.count     else         activecell.offset(0, 1) = "(not matched)"     end if end sub 

in end, strreplace.count shows 1, whole string ftp_01_01_06_results\4f\acc2x8r133371_sasssd_run1

use .submatches capturing groups values:

private sub parsefilename(strinput string)     dim regex new regexp     dim strpattern string     dim strreplace matchcollection     dim long      'sample string \\work_dir\ftp\results\reva\ftp_01_01_06_results\4f\acc2x2r33371_sasssd_run1     strpattern = "ftp_(\w+)_results\\(\w+)\\([\d,\d]+)_(sas|sata)(hdd|ssd)_run(\d)"      regex         .global = true         .multiline = false         .ignorecase = false         .pattern = strpattern     end      if regex.test(strinput)         set strreplace = regex.execute(strinput)         activecell.offset(0, 1) = strreplace.count         = 0 5             activecell.offset(i + 1, 1) = strreplace(0).submatches(i)         next     else         activecell.offset(0, 1) = "(not matched)"     end if end sub 

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