post - PHP $_FILES["fileToUpload"]["tmp_name"] -

how can turn $_files["filetoupload"]["tmp_name"] variable used in move_uploaded_file?

this works:

  $filename = compress_image(($_files["filetoupload"]["tmp_name"]), $url, 30); 

but trying this:

  $filename = compress_image($images, $url, 30); 

but, when above not work.

one alternative starting on was:

  file_put_contents($target_file , $image); 

in case, image named directory properly, image broken.

to clarify:

need turn ($_files["filetoupload"]["tmp_name"]) variable result of

    ob_start(); echo imagejpeg($image,null,30);      $image =ob_get_clean();      ob_end_clean();      $image = addslashes($image);  

i need use $image save directory. $image has been stored mysql. have tried encode, , decode on $image, still no luck.

let me explain problem step-by-step:

the mess starts @ line:

$image = imagecreatefromstring(file_get_contents($_files['filetoupload']['tmp_name'])); 

problems:

• never use temp file process; move uploaded file permanent place move_uploaded_file() first
• use of file_get_contents() unnecessary; can use imagecreatefromjpeg() (and other formats, gif, png, etc) replace imagecreatefromstring(file_get_contents()) things

---

here compress_image() function:

function compress_image($source_url, $destination_url, $quality) {     $info = getimagesize($source_url);     if ($info['mime'] == 'image/jpeg')  {         $image = imagecreatefromjpeg($source_url);     } elseif ($info['mime'] == 'image/gif') {         $image = imagecreatefromgif($source_url);     } elseif ($info['mime'] == 'image/png') {         $image = imagecreatefrompng($source_url);     }     imagejpeg($image, $destination_url, $quality);     return $destination_url; } 

problems:

• if mime none of above, imagejpeg() fail (but didn't cater it; check return value of function)
• you didn't check $destination_url writable & exist or not

---

next, assumes compress_image() works , returns $destination_url valid jpeg created @ path, following codes cause further problems:

$sql = "insert fffdf (`user_id`,`imit`) values ('9','$image')"; if (mysqli_query($conn, $sql)) {   echo "new record created successfully"; } else {   echo "error: " . $sql . "<br>" . mysqli_error($conn); } 

problems:

• why save $image directly db? it's bad practice store image data in db. save path instead whenever possible

• $image inaccessible here; scope of $image stays in function compress_image(), $image still contains value before compress_image(), unless use global $image; in compress function (which not suggested). pass $image function parameters reference:

  function compress_image(&$image, $destination_url, $quality)

you don't need $source_url if have image data stored in $image.

hope above helps.