python - urllib does not handle # character properly -

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i have url looks follows: 

http://me:me1234#@localhost:8080/

when run urlparse on url, instead of netlocpath returning me:me1234#@localhost:8080 returns me:me1234.

from six.moves.urllib import parse o=parse.urlparse('http://me:me1234#@localhost:8080/') print o

parseresult(scheme='http', netloc='me:me1234', path='', params='', query='', fragment='@localhost:8080/')

any idea how why failing parse #? think pretty standard url.

it's fragment. need to encode first:

from six.moves.urllib import parse o=parse.urlparse('http://me:me1234%23@localhost:8080/') print o

this should work needs.


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