python - pass argument to function in a dictionary -

i've switch, given option call function e.g.

#... capture option op = getoption() #.. capture metric mt = getmetric()  def zipcode():     print "you typed zero.\n" def desc():     print "n perfect square\n" def address():     print "n number\n"  #call desired option options= {0 : zipcode,           1 : code,           2 : desc,           3 : address }  options[op]() 

i trying pass parameter (mt) options dict call function, i'm not being able so.

if op received 1 , mt foo, how call right function (zipcode) done passing mt parameter?

ideally: options[op](mt) , defining 1 parameter in function?

thanks

your code not indented properly, important in python , cause syntax errors is.

however, suggesting work perfectly.

consider following:

def multiply(m,n):     return n*n  def add(m,n)     return m,n  my_math = { "+":add,             "*":multiply} 

you call follows:

>>> print my_math["+"](1,2) 3 >>> print my_math["*"](4,5) 20