php - How to know if a script was included inside another script -

i new php , using incorrect approach because not used think php programmer.

i have files include other files dependencies, these files need have global code executed if $_post contains values, this

if (isset($_post["somevalue"]))  {     /* code goes here */  } 

all files contain code section, each 1 it's own code of course.

the problem since files can included in 1 of these files, code section describe executed in every included file, when post trhough ajax , explicitly use url of script want post to.

i tried using $_server array try , guess script used post request, , though worked because right script, same script every included file.

question is:

• is there way know if file included file can test , skip code execute if $_post contains required values?

note: files generated using python script uses c library scans database it's tables , constraints, c library mine python script, work , if there fix single file, needs performed python script.

i tell reader (potential answerer) because think makes clear don't need solution works on existant files, because can re-generated.

from sounds of make improvements on code structure avoid problem. however, information given simple flag variable should trick:

if (!isset($postcodeexecuted) && isset($_post["somevalue"])) {     /* code goes here */     $postcodeexecuted = true; } 

this variable set in global namespace , therefore available everywhere.