c - Print ellipse using characters -

the general equation rotated ellipse centered @ (h, k) has form a(x − h)^2 + b(x − h)(y − k) + c(y − k)^2 = 1, , c positive, , b^2 − 4ac < 0.

i'm trying print out filled ellipse using formula, prints out *s on first line , \n's next 39 lines, loop breaks. dont why happening.

here lines of code, i'm using input a=0.04, b=0.001, c=0.01, h , k =6. should print 5x10 ellipse, center 6, 6.

int x=0, y=0, h, k; float a, b, c;  printf("input "); scanf("%f", &a); printf("input b "); scanf("%f", &b); printf("input c "); scanf("%f", &c); printf("input h "); scanf("%f", &h); printf("input k "); scanf("%f", &k);  while(1){     if(y>=40){         break;     }     if((a*((x-h)*(x-h)))+(b*(x-h)*(y-k))+(c*((y-k)*(y-k)))<=1){         printf("*");         x++;         continue;     }      if(x>=80){         printf("\n");         y++;         continue;     }     else{         printf(" ");         x++;         continue;     } }    return 0; 

this trivial fix-up of code, converted mcve (minimal, complete, verifiable example), produces more-or-less elliptical output shown when run it:

#include <stdio.h>  int main(void) {     float = 0.04;     float b = 0.001;     float c = 0.01;     int h = 6;     int k = 6;     int x = 0;     int y = 0;      while (y < 40)     {         if ((a * (x - h) * (x - h)) +             (b * (x - h) * (y - k)) +             (c * (y - k) * (y - k)) <= 1.0)         {             printf("*");             x++;         }         else if (x >= 80)         {             printf("\n");             y++;             x = 0;         }         else         {             printf(" ");             x++;         }     }     return 0; } 

sample output:

$ ./ellipse    ********        *********   *********   *********   *********   *********  ***********   *********   *********   *********   *********   *********   ********    *******    ******     *****       * 

(plus number of blank lines).

^{since bulk of work done in comments , not me, i've made answer community wiki.}