html - PHP and MySQL query based on user input not working -

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i creating users database there 4 fields: id, username, password, , occupation. test database. tried querying db table , worked have lot of trouble having user input , mysql query based off of it. run apache server in linux (debian, ubuntu).

i have 2 pages. first 1 bare-bone test index page. there textboxes people input easy info register info in db. here code it:

<html>  <form action="reg.php" method="post">    username:    <input type="text" name="u">password:    <input type="password" name="p">occupation:    <input type="text" name="o">    <input type="submit" value="register">      </form>    </html>

after submit button clicked. goes reg.php file. gets complicated. page goes blank!!! nothing displayed or inputted in db. normal queries work well, when user interaction added, wrong. here code reg.php:

<?php  $un = $_post["u"]  $pk = $_post["p"]  $ok = $_post["o"]  $u = mysql_real_escape_string($un);  $p = mysql_real_escape_string($pk);    $o = mysql_real_escape_string($ok);        $link = mysql_connect('localhost', 'root', 'randompassword');  if (!$link){  die(' oops. have problem here: ' . mysql_error());  }    if ($link){  echo 'connected succesfully';  }    mysql_select_db("forum") or die(' oops. have problem here: ' . mysql_error());  $data = mysql_query("insert users (username, password, occupation) values ('{$u}', '{$p}', '{$o}')");    ?>

can hep me correct code make work? thank time. appreciated.

edit: noticed did not add semicolons in first 3 lines. after doing got error: "you have error in sql syntax; check manual corresponds mysql server version right syntax use near '{'', '', '')' @ line 1." can explain why?

edit: website on local machine... on apache server on linux

mysql_real_escape_string() requires db connection. try ....

<?php $un = $_post["u"]; $pk = $_post["p"]; $ok = $_post["o"];  $link = mysql_connect('localhost', 'root', 'randompassword'); if (!$link){   die(' oops. have problem here: ' . mysql_error()); }  if ($link){   echo 'connected succesfully'; }  mysql_select_db("forum") or die(' oops. have problem here: ' . mysql_error());  $u = mysql_real_escape_string($un); $p = mysql_real_escape_string($pk); $o = mysql_real_escape_string($ok); $sql = "insert users (username, password, occupation) values ('$u', '$p', '$o')"; $ins_sql = mysql_query($sql); if($ins_sql) {   echo 'inserted new record.'; }else{   echo 'insert failed.'; } ?>

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